Alpha.Z寫的數字轉換為中文的類的補充

發表于:2007-07-14來源:作者:點擊數: 標簽:
去掉了一些多余的零 ? php // 諸海加 2000-7-19 // xiaocui 2000-7-26 class ChineseNumber { var $basical=array(0=零,一,二,三,四,五,六,七,八,九); //var $basical=array(0=零,壹,貳,叁,肆,伍,陸,柒,捌,玖); var $advanced=array(1=十,百,千); //var $adv
去掉了一些多余的零

<?php
// 諸海加 2000-7-19
// xiaocui 2000-7-26

class ChineseNumber
{
    var $basical=array(0=>"零","一","二","三","四","五","六","七","八","九");
    //var $basical=array(0=>"零","壹","貳","叁","肆","伍","陸","柒","捌","玖");
    var $advanced=array(1=>"十","百","千");
    //var $advanced=array(1=>"拾","佰","仟");
    var $top=array(1=>"萬","億");

    var $level;            // 以4位為一級

    // 先實現萬一下的數的轉換
    function ParseNumber($number)
    {
        if ($number>999999999999)        // 只能處理到千億。
            return "數字太大,無法處理。抱歉!";
        if ($number==0)
            return "零";

        for($this->level=0;$number>0.0001;$this->level++,$number=floor($number / 10000))
        {
            // 對于中文來說,應該是4位為一組。
            // 四個變量分別對應 個、十、百、千 位。
            $n1=substr($number,-1,1);
            if($number>9)
                $n2=substr($number,-2,1);
            else
                $n2=0;
            if($number>99)
                $n3=substr($number,-3,1);
            else
                $n3=0;
            if($number>999)
                $n4=substr($number,-4,1);
            else
                $n4=0;

            if($n4)
                $parsed[$this->level].=$this->basical[$n4].$this->advanced[3];
            else
                if(($number/10000)>=1)        // 千位為0,數值大于9999的情況
                    $parsed[$this->level].="零";
            if($n3)
                $parsed[$this->level].=$this->basical[$n3].$this->advanced[2];
            else
                if(!ereg("零$",$parsed[$this->level]) && ($number / 1000)>=1)    // 不出現連續兩個“零”的情況
                    $parsed[$this->level].="零";
            if($n2)
                $parsed[$this->level].=$this->basical[$n2].$this->advanced[1];
            else
                if(!ereg("零$",$parsed[$this->level]) && ($number / 100)>=1)    // 不出現連續兩個“零”的情況
                    $parsed[$this->level].="零";
            if($n1)
                $parsed[$this->level].=$this->basical[$n1];

            if($parsed[$this->level]!="零")
            {
               if(ereg("零$",$parsed[$this->level]))
                  $parsed[$this->level]=substr($parsed[$this->level],0,strlen($parsed[$this->level])-2);
               if($this->level>0)
                  $result=$parsed[$this->level].$this->top[$this->level].$result;
               else
                  $result=$parsed[$this->level].$result;
            }
        }
        //for($this->level-=1;$this->level>=0;$this->level--)
        //{
        //    $result.=$parsed[$this->level].$this->top[$this->level];
        //}

        //if(ereg("零$",$result))
        //    $result=substr($result,0,strlen($result)-2);

        return $result;
        
    }
};

$c=new ChineseNumber();
echo $c->ParseNumber(100000000001);
?>

原文轉自:http://www.anti-gravitydesign.com

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